Date :: subtractMonths - Subtract month from date value
The number of months passed in iMonths is subtracted from the date value. Year may change, when month becomes less than 1. Usually, day remains unchanged, but will be adjusted, when the new month value does not have the resulting day
Date date(31,3,2009);
date.subtractMonths(1); // day becomes: 2009-28-2
Return value: Date ( odaba::Date & )
The date contains day, month and year, but not the time.
Implementation details
odaba::Date &
Date  :: subtractMonths ( int32 iMonths )
- iMonths
- Months
Time span in months.